在Spring Webservice中,不能从START_ARRAY标记反序列化对象的实例

我现在无法连接到我的web服务在Android上。 我使用jackson-core / databind / annotation-2.2.4和Spring RESTWebService。 如果我从浏览器访问URL,我可以看到JSON响应:(服务器返回List \ Shop \看起来像:)

[{"name":"shopqwe","mobiles":[],"address":{"town":"city", "street":"streetqwe","streetNumber":"59","cordX":2.229997,"cordY":1.002539}, "shoe" [{"shoeName":"addidas","number":"631744030","producent":"nike","price":999.0, "sizes":[30.0,35.0,38.0]}] 

从客户端端点(Android应用程序),我收到此错误消息:

 08-26 17:43:07.406: E/AllShopsAsyc(28203): Could not read JSON: Can not deserialize instance of com.auginzynier.data.ShopContainer out of START_ARRAY token 08-26 17:43:07.406: E/AllShopsAsyc(28203): at [Source: com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1, column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of com.auginzynier.data.ShopContainer out of START_ARRAY token 08-26 17:43:07.406: E/AllShopsAsyc(28203): at [Source: com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1, column: 1] 08-26 17:43:07.406: E/AllShopsAsyc(28203): org.springframework.http.converter.HttpMessageNotReadableException: Could not read JSON: Can not deserialize instance of com.auginzynier.data.ShopContainer out of START_ARRAY token 

我的服务器请求

 RestTemplate restTemplate = new RestTemplate(); restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter()); ShopContainer response = restTemplate.getForObject(url, ShopContainer.class); 

ShopContainer在哪里:

 public class ShopContainer { private List<Shop> shops; 

商店,地址和鞋子的结构是(我在这里错过获得者和接受者):

 public class Shop { @JsonProperty("name") private String name; @JsonProperty("mobiles") private List<String> mobiles = new ArrayList<String>(); @JsonProperty("address") private Address address; @JsonProperty("shoe") private List<Shoe> shoe = new ArrayList<Shoe>(); public class Address { @JsonProperty("town") private String town; @JsonProperty("street") private String street; @JsonProperty("streetNumber") private String streetNumber; @JsonProperty("cordX") private Double cordX; @JsonProperty("cordY") private Double cordY; public class Shoe { @JsonProperty("shoeName") private String shoeName; @JsonProperty("number") private String number; @JsonProperty("producent") private String producent; @JsonProperty("price") private Double price; @JsonProperty("sizes") private List<Double> sizes = new ArrayList<Double>(); 

我环顾这里和谷歌,但仍然无法弄清楚我在这一点上失踪的任何反应将是非常有益的。

问候。

@UPDATE

我通过在服务器RequestMetod.GET中使用jackson ObjectMaper修复了JSON格式。 现在它返回一个string。

 list is List<Shop> ObjectMapper mapper = new ObjectMapper(); mapper.writeValue(new File("D:\\Android\\shop.json"), list); System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list)); return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list); 

控制台中的JSON如下所示:

 [ { "name" : "shopqwe", "mobiles" : [ ], "address" : { "town" : "city", "street" : "streetqwe", "streetNumber" : "59", "cordX" : 2.229997, "cordY" : 2.002539 }, "shoe" : [ { "shoeName" : "addidas", "number" : "631744033", "producent" : "nike", "price" : 10.0, "sizes" : [ 30.0, 35.0, 38.0 ] } ] } ] 

请求仍然不起作用 – 错误是一样的。

你的json包含一个数组,但是你试图把它parsing为对象。 发生此错误是因为对象必须从{开始。

你有2个选项:

  1. 您可以摆脱ShopContainer类并使用Shop[]来代替

     ShopContainer response = restTemplate.getForObject( url, ShopContainer.class); 

    用。。。来代替

     Shop[] response = restTemplate.getForObject(url, Shop[].class); 

    然后让对象形成它或任何你需要的东西。

  2. 你可以改变你的服务器来返回对象而不是列表

     return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list); 

    用。。。来代替

     return mapper.writerWithDefaultPrettyPrinter().writeValueAsString( new ShopContainer(list)); 

理所当然,你发布的JSON实际上是你在浏览器中看到的,那么问题就是JSON本身。

您发布的JSON片段格式不正确。

你已经发布:

 [{ "name" : "shopqwe", "mobiles" : [], "address" : { "town" : "city", "street" : "streetqwe", "streetNumber" : "59", "cordX" : 2.229997, "cordY" : 1.002539 }, "shoe"[{ "shoeName" : "addidas", "number" : "631744030", "producent" : "nike", "price" : 999.0, "sizes" : [30.0, 35.0, 38.0] }] 

而正确的JSON将是:

 [{ "name" : "shopqwe", "mobiles" : [], "address" : { "town" : "city", "street" : "streetqwe", "streetNumber" : "59", "cordX" : 2.229997, "cordY" : 1.002539 }, "shoe" : [{ "shoeName" : "addidas", "number" : "631744030", "producent" : "nike", "price" : 999.0, "sizes" : [30.0, 35.0, 38.0] } ] } ]