Swift：如何使UILabel可点击？

我想做一个UILabel点击。

我试过这个，但是不起作用：

class DetailViewController: UIViewController { @IBOutlet weak var tripDetails: UILabel! override func viewDidLoad() { super.viewDidLoad() ... let tap = UITapGestureRecognizer(target: self, action: Selector("tapFunction:")) tripDetails.addGestureRecognizer(tap) } func tapFunction(sender:UITapGestureRecognizer) { print("tap working") } } 

Answer 1

你有没有尝试在tripDetails标签上设置userInteractionEnabled为true ？ 这应该工作。

Answer 2

Swift 3更新

更换

 Selector("tapFunction:") 

同

 #selector(DetailViewController.tapFunction) 

例：

 class DetailViewController: UIViewController { @IBOutlet weak var tripDetails: UILabel! override func viewDidLoad() { super.viewDidLoad() ... let tap = UITapGestureRecognizer(target: self, action: #selector(DetailViewController.tapFunction)) tripDetails.isUserInteractionEnabled = true tripDetails.addGestureRecognizer(tap) } func tapFunction(sender:UITapGestureRecognizer) { print("tap working") } } 

Answer 3

Swift 3更新

 yourLabel.isUserInteractionEnabled = true 

Answer 4

您需要启用该标签的用户交互…..

例如

yourLabel.userInteractionEnabled = true

Answer 5

SWIFT 4.0更新

  @IBOutlet weak var tripDetails: UILabel! override func viewDidLoad() { super.viewDidLoad() let tap = UITapGestureRecognizer(target: self, action: #selector(GameViewController.tapFunction)) tripDetails.isUserInteractionEnabled = true tripDetails.addGestureRecognizer(tap) } @objc func tapFunction(sender:UITapGestureRecognizer) { print("tap working") } 

Answer 6

对于SWIFT 3.0，你也可以改变手势长按持续时间

 label.isUserInteractionEnabled = true let longPress:UILongPressGestureRecognizer = UILongPressGestureRecognizer.init(target: self, action: #selector(userDragged(gesture:))) longPress.minimumPressDuration = 0.2 label.addGestureRecognizer(longPress)