在我的网站上,我使用jQuery钩住元素的事件,即超链接。 由于这些超链接只在当前页面上执行操作,并且不会导致任何地方,所以我一直在将“#”的href属性放在: <a href="#">My Link</a> 然而,在一些浏览器中,这会导致页面向右滚动到顶部,这显然是不受欢迎的行为。 我试过使用一个空白的href值,或不包括一个,但然后鼠标hover时不会更改为手形光标。 我应该在那里放什么?
我在表格结构中做了一个错误的计算。 下面的代码是一个乐透游戏(我认为是一段已知的代码) 有没有办法在充满数字的表顶部添加一行? 我真的不知道该怎么做。 http://www.coldcharlie.nl/lotto/ <script type="text/javascript"> (function() { var players = { Joop : ["6","8","16","18","26","28","32","36","38","41"], Marijke: ["7","10","14","18","24","29","30","34","39","40"], Michel : ["4","5","11","16","21","27","33","36","42","44"], Mario : ["6","9","18","25","32","35","39","40","43","45"], Diana : ["2","6","8","17","22","23","33","36","42","45"], Agnes : ["3","5","10","15","26","29","32","37","41","44"], Chris : ["5","7","8","9","11","12","16","28","30","32"], Jeannette: ["1","2","4","7","8","11","13","28","30","38"], Wieger: ["1","2","3","7","10","13","14","22","23","27"], Anita: ["6","13","15","17","21","26","32","33","43","45"], Thea: ["1","3","5","7","10","17","19","20","22","38"], Danny: ["3","7","11","15","22","28","32","37","40","43"], Cindy: ["2","4","16","18","21","24","33","38","41","44"], Hanneke: ["1","3","4","12","18","21","25","30","36","40"], Willem: ["3","9","17","21","27","33","35","39","41","42"] }, draws = [ { when: […]
有一种方法可以在给定的时间段之后使用JQueryredirect到特定的URL吗?
无论如何,点击事件被触发时,得到类。 我的代码如下,它只适用于id而不是类。 HTML: <html> <body> <a href="#" id="kana1" class="konbo">click me 1</a> <a href="#" id="kana2" class="kinta">click me 2</a> </body> </html> JQuery的: $(document).ready(function() { $("a").click(function(event) { alert(event.target.id+" and "+event.target.class); }); }); jsfiddle代码在这里
我正在debugging一个可视化的composer php插件,当我更新Wordpress到4.5后,我无法弄清楚它为什么会抛出一个TypeError。 控制台中的错误消息: JQMIGRATE: Migrate is installed, version 1.4.0 load-scripts.php?…. Uncaught TypeError: $template.get is not a function composer-view.js?ver=4.1.1.1:73 在下面的代码中只能find$template 。 我明白,这不是很多情况下,但我怎样才能解决这个错误? /** * Convert html into correct element * @param html */ html2element: function(html) { var attributes = {}, $template; if (_.isString(html)) { this.template = _.template(html); $template = $(this.template(this.model.toJSON()).trim()); } else { this.template = html; […]
我有一个string"MySites" 。 我想在“ My和“ Sites之间放置一个空格。 我怎样才能做到这一点在jQuery或JavaScript?
我使用Bootstrap 3.3创build了一个carousel ,它可以在我的本地机器上运行,但是当我将上面的bootstrap js文件与其他文件一起编译到一个文件的服务器上时,出现这个错误: Cannot read property 'offsetWidth' of undefined – 有没有人遇到过这个问题,并有任何已知的解决scheme?
我知道有很多关于replace的问题,但似乎没有答案适用于我的情况。 html: <div id="foo"></div> 我希望#foo被淡出,然后我想用淡淡的东西来replace整个东西(不仅仅是内容)。 谢谢
我正在使用jQuery库来实现拖放。 如何获取正在被拖放的元素? 我想获得div内图像的id。 以下元素被拖动: <div class="block"> <asp:Image ID="Image9" AlternateText="10/12/2008 – Retina" Width=81 Height=84 ImageUrl="~/uploads/ImageModifier/retina.jpg" runat=server /> </div> 我从他们的例子中有标准的下降function: $(".drop").droppable({ accept: ".block", activeClass: 'droppable-active', hoverClass: 'droppable-hover', drop: function(ev, ui) { } }); 我已经尝试过各种ui.id等似乎没有工作。
由于我使用jQuery,所以任何解决scheme都可以。 理想情况下,我想知道两个,但。 我已经有箭头键绑定到我的页面上的另一个function(使用jQuery),但让他们导致页面滚动除此之外,导致我的问题。 我可能曾经知道这一点,但我不记得了。