Apache HttpClient(4.1及更高版本):如何做基本身份validation?

如何为httpClient库的默认客户端添加基本身份validation? 我已经看到他们使用client.getCredentialProvider()例子,但是我认为所有这些方法都是针对库版本4.0.1或3.x的。 有没有一个新的例子如何做到这一点? 非常感谢。

我们使用HttpClient进行基本身份validation,但是我们不使用CredentialProvider 。 代码如下:

 HttpClient client = factory.getHttpClient(); //or any method to get a client instance Credentials credentials = new UsernamePasswordCredentials(username, password); client.getState().setCredentials(AuthScope.ANY, credentials); 

更新:在评论中指出, HttpClient.getState() 方法在API的3.x版本中可用。 但是, 较新版本的API不支持该方法。

 CredentialsProvider credentialsProvider = new BasicCredentialsProvider(); credentialsProvider.setCredentials(AuthScope.ANY, new UsernamePasswordCredentials("username", "password")); CloseableHttpClient httpClient = HttpClientBuilder.create().setDefaultCredentialsProvider(credentialsProvider).build(); 

你没有从网站上下载这个例子吗?例子如下:httpcomponents-client-4.1.3 \ examples \ org \ apache \ http \ examples \ client

至于https,请参阅ClientAuthentication.java:

 /* * ==================================================================== * * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. * ==================================================================== * * This software consists of voluntary contributions made by many * individuals on behalf of the Apache Software Foundation. For more * information on the Apache Software Foundation, please see * <http://www.apache.org/>. */ package org.apache.http.examples.client; import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.auth.AuthScope; import org.apache.http.auth.UsernamePasswordCredentials; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.DefaultHttpClient; import org.apache.http.util.EntityUtils; /** * A simple example that uses HttpClient to execute an HTTP request against * a target site that requires user authentication. */ public class ClientAuthentication { public static void main(String[] args) throws Exception { DefaultHttpClient httpclient = new DefaultHttpClient(); try { httpclient.getCredentialsProvider().setCredentials( new AuthScope("localhost", 443), new UsernamePasswordCredentials("username", "password")); HttpGet httpget = new HttpGet("https://localhost/protected"); System.out.println("executing request" + httpget.getRequestLine()); HttpResponse response = httpclient.execute(httpget); HttpEntity entity = response.getEntity(); System.out.println("----------------------------------------"); System.out.println(response.getStatusLine()); if (entity != null) { System.out.println("Response content length: " + entity.getContentLength()); } EntityUtils.consume(entity); } finally { // When HttpClient instance is no longer needed, // shut down the connection manager to ensure // immediate deallocation of all system resources httpclient.getConnectionManager().shutdown(); } } } 

所以简而言之:

 DefaultHttpClient httpclient = new DefaultHttpClient(); httpclient.getCredentialsProvider().setCredentials( new AuthScope("localhost", 443), new UsernamePasswordCredentials("username", "password")); 

4.3的另一个现代select是使用Fluent扩展:

 Executor executor = Executor.newInstance() .auth(new HttpHost("somehost"), "username", "password") .auth(new HttpHost("securehost", 443, "https"), "username", "password") // https example .auth(new HttpHost("myproxy", 8080), "username", "password") .authPreemptive(new HttpHost("myproxy", 8080)); String content = executor.execute(Request.Get("http://somehost/")) .returnContent().asString(); 

DefaultHttpClient有getCredentialsProvider(),但是HttpClient不。 您需要声明DefaultHttpClient客户端= …而不是HttpClient客户端= …

我有这个要求调用一个URL与基本authentication,这也需要代理设置。 这是为我工作。

  import java.io.IOException; import java.io.InputStream; import java.io.StringReader; import java.util.HashMap; import java.util.Map; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.ParserConfigurationException; import org.apache.commons.httpclient.Credentials; import org.apache.commons.httpclient.HostConfiguration; import org.apache.commons.httpclient.HttpClient; import org.apache.commons.httpclient.HttpMethod; import org.apache.commons.httpclient.HttpStatus; import org.apache.commons.httpclient.UsernamePasswordCredentials; import org.apache.commons.httpclient.auth.AuthScope; import org.apache.commons.httpclient.methods.GetMethod; import org.w3c.dom.*; import javax.xml.parsers.*; import org.xml.sax.InputSource; import org.xml.sax.SAXException; public class TestResponse { public final static String TESTURL="https://myURL"; private static final String PROXY_HOST = "www2.proxyXYS"; private static final int PROXY_PORT = 8080; public static void main (String args[]) { HttpClient client = new HttpClient(); HttpMethod method = new GetMethod(TESTURL); HostConfiguration config = client.getHostConfiguration(); config.setProxy(PROXY_HOST, PROXY_PORT); String username = "User"; String password = "Pa55w0rd"; Credentials credentials = new UsernamePasswordCredentials(username, password); AuthScope authScope = new AuthScope(PROXY_HOST, PROXY_PORT); client.getState().setProxyCredentials(authScope, credentials); client.getState().setCredentials(AuthScope.ANY, credentials); try { client.executeMethod(method); String response = method.getResponseBodyAsString(); if (method.getStatusCode() == HttpStatus.SC_OK) { response = method.getResponseBodyAsString(); } } catch (IOException e) { e.printStackTrace(); } finally { method.releaseConnection(); } } }