TypeError：不能将“int”对象隐式转换为str

我正在尝试编写一个文本游戏，并且在我定义的函数中遇到了一个错误，让您在创buildangular色之后基本上可以使用技能点。 起初，错误指出，我正试图从这部分代码中的整数减去一个string： balance - strength 。 显然这是错误的，所以我用strength = int(strength)修正它…但是现在我得到了这个我以前从来没有见过的错误（新程序员），我很难确定它到底想告诉我什么，我修复它。

这里是我的代码为不工作的部分function：

 def attributeSelection(): balance = 25 print("Your SP balance is currently 25.") strength = input("How much SP do you want to put into strength?") strength = int(strength) balanceAfterStrength = balance - strength if balanceAfterStrength == 0: print("Your SP balance is now 0.") attributeConfirmation() elif strength < 0: print("That is an invalid input. Restarting attribute selection. Keep an eye on your balance this time!") attributeSelection() elif strength > balance: print("That is an invalid input. Restarting attribute selection. Keep an eye on your balance this time!") attributeSelection() elif balanceAfterStrength > 0 and balanceAfterStrength < 26: print("Ok. You're balance is now at " + balanceAfterStrength + " skill points.") else: print("That is an invalid input. Restarting attribute selection.") attributeSelection() 

当我到达shell的这部分代码的时候，这里是我得到的错误：

  Your SP balance is currently 25. How much SP do you want to put into strength?5 Traceback (most recent call last): File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 205, in <module> gender() File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 22, in gender customizationMan() File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 54, in customizationMan characterConfirmation() File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 93, in characterConfirmation characterConfirmation() File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 85, in characterConfirmation attributeSelection() File "C:\Python32\APOCALYPSE GAME LIBRARY\apocalypseGame.py", line 143, in attributeSelection print("Ok. You're balance is now at " + balanceAfterStrength + " skill points.") TypeError: Can't convert 'int' object to str implicitly 

有谁知道如何解决这个问题？ 谢谢。

Answer 1

你不能连接一个string与一个int 。 您需要使用str函数将int转换为string ，或使用formatting来设置输出的格式。

更改： –

 print("Ok. Your balance is now at " + balanceAfterStrength + " skill points.") 

至： –

 print("Ok. Your balance is now at {} skill points.".format(balanceAfterStrength)) 

要么： –

 print("Ok. Your balance is now at " + str(balanceAfterStrength) + " skill points.") 

或根据注释使用,将不同的string传递给您的printfunction，而不是使用+连接：

 print("Ok. Your balance is now at ", balanceAfterStrength, " skill points.")