在SQL列中查找最常用的值

我怎样才能findSQL表中给定列中最频繁的值？

例如，对于这个表，它应该返回two因为它是最常见的值：

 one two two three 

Answer 1

 SELECT `value`, COUNT(`value`) AS `value_occurrence` FROM `my_table` GROUP BY `value` ORDER BY `value_occurrence` DESC LIMIT 1; 

Answer 2

尝试像这样：

 SELECT `column` FROM `your_table` GROUP BY `column` ORDER BY COUNT(*) DESC LIMIT 1; 

Answer 3

让我们把表名称作为city tblperson和列名。 我想从城市列中找回最重复的城市：

  select city,count(*) as nor from tblperson group by city having count(*) =(select max(nor) from (select city,count(*) as nor from tblperson group by city) tblperson) 

这里nor是一个别名。

Answer 4

下面的查询似乎在SQL Server数据库中对我有用：

 select column, COUNT(column) AS MOST_FREQUENT from TABLE_NAME GROUP BY column ORDER BY COUNT(column) DESC 

结果：

 column MOST_FREQUENT item1 highest count item2 second highest item3 third higest .. .. 

Answer 5

用于SQL Server。

由于没有限制命令的支持。

哟可以使用top 1命令来查找在这种情况下特定列中的最大值（值）

 SELECT top1 `value`, COUNT(`value`) AS `value_occurrence` FROM `my_table` GROUP BY `value` ORDER BY `value_occurrence` DESC; 

Answer 6

假设表格是' SalesLT.Customer '，你试图找出的列是' CompanyName '，而AggCompanyName是一个别名。

 Select CompanyName, Count(CompanyName) as AggCompanyName from SalesLT.Customer group by CompanyName Order By Count(CompanyName) Desc; 

Answer 7

如果您不能使用LIMIT或LIMIT不是您的查询工具的选项。 你可以使用“ROWNUM”来代替，但是你需要一个子查询：

 SELECT FIELD_1, ALIAS1 FROM(SELECT FIELD_1, COUNT(FIELD_1) ALIAS1 FROM TABLENAME GROUP BY FIELD_1 ORDER BY COUNT(FIELD_1) DESC) WHERE ROWNUM = 1