PHP：从时间戳生成相对date/时间
我基本上是试图将Unix时间戳（time（）函数）转换为与过去和未来date兼容的相对date/时间。 所以产出可以是：
2个星期前
1小时60分钟前
15分54秒前
10分15秒后
首先，我试图编写这个代码，但是做了一个很难维护的function，然后我在网上search了几个小时，但是我能find的只是一个脚本，只能产生一部分时间（呃：“1小时前”纪要）。
你有一个脚本，已经这样做？
这个function给你“1小时前”或“明天”，就像'now'和'specific timestamp'之间的结果一样。
function time2str($ts) { if(!ctype_digit($ts)) $ts = strtotime($ts); $diff = time() - $ts; if($diff == 0) return 'now'; elseif($diff > 0) { $day_diff = floor($diff / 86400); if($day_diff == 0) { if($diff < 60) return 'just now'; if($diff < 120) return '1 minute ago'; if($diff < 3600) return floor($diff / 60) . ' minutes ago'; if($diff < 7200) return '1 hour ago'; if($diff < 86400) return floor($diff / 3600) . ' hours ago'; } if($day_diff == 1) return 'Yesterday'; if($day_diff < 7) return $day_diff . ' days ago'; if($day_diff < 31) return ceil($day_diff / 7) . ' weeks ago'; if($day_diff < 60) return 'last month'; return date('F Y', $ts); } else { $diff = abs($diff); $day_diff = floor($diff / 86400); if($day_diff == 0) { if($diff < 120) return 'in a minute'; if($diff < 3600) return 'in ' . floor($diff / 60) . ' minutes'; if($diff < 7200) return 'in an hour'; if($diff < 86400) return 'in ' . floor($diff / 3600) . ' hours'; } if($day_diff == 1) return 'Tomorrow'; if($day_diff < 4) return date('l', $ts); if($day_diff < 7 + (7 - date('w'))) return 'next week'; if(ceil($day_diff / 7) < 4) return 'in ' . ceil($day_diff / 7) . ' weeks'; if(date('n', $ts) == date('n') + 1) return 'next month'; return date('F Y', $ts); } } function relativeTime($time) { $d[0] = array(1,"second"); $d[1] = array(60,"minute"); $d[2] = array(3600,"hour"); $d[3] = array(86400,"day"); $d[4] = array(604800,"week"); $d[5] = array(2592000,"month"); $d[6] = array(31104000,"year"); $w = array(); $return = ""; $now = time(); $diff = ($now-$time); $secondsLeft = $diff; for($i=6;$i>-1;$i--) { $w[$i] = intval($secondsLeft/$d[$i][0]); $secondsLeft -= ($w[$i]*$d[$i][0]); if($w[$i]!=0) { $return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." "; } } $return .= ($diff>0)?"ago":"left"; return $return; }
用法：
echo relativeTime((time()-256)); 4 minutes 16 seconds ago
这是我写的。 显示相对于今天的date的过去的date。
/** * @param $date integer of unixtimestamp format, not actual date type * @return string */ function zdateRelative($date) { $now = time(); $diff = $now - $date; if ($diff < 60){ return sprintf($diff > 1 ? '%s seconds ago' : 'a second ago', $diff); } $diff = floor($diff/60); if ($diff < 60){ return sprintf($diff > 1 ? '%s minutes ago' : 'one minute ago', $diff); } $diff = floor($diff/60); if ($diff < 24){ return sprintf($diff > 1 ? '%s hours ago' : 'an hour ago', $diff); } $diff = floor($diff/24); if ($diff < 7){ return sprintf($diff > 1 ? '%s days ago' : 'yesterday', $diff); } if ($diff < 30) { $diff = floor($diff / 7); return sprintf($diff > 1 ? '%s weeks ago' : 'one week ago', $diff); } $diff = floor($diff/30); if ($diff < 12){ return sprintf($diff > 1 ? '%s months ago' : 'last month', $diff); } $diff = date('Y', $now) - date('Y', $date); return sprintf($diff > 1 ? '%s years ago' : 'last year', $diff); }
我喜欢xdebug的relativeTime函数。 问题是我需要它有一定的粒度。
换句话说，如果我决定，在几秒钟或几分钟停下来。 所以现在，
echo fTime(strtotime('-23 hours 5 minutes 55 seconds'),0);
会显示，
23小时，5分钟前
代替
23小时，5分钟，55秒前
如果达到了较高的时间量，我也希望它不会在arrays中降低。 所以如果显示几年，我只想显示几年和几个月。 所以现在，
echo fTime(strtotime('-1 year 2 months 3 weeks 4 days 16 hours 15 minutes 22 seconds'),0);
会显示
1年，2个月前
代替
1年，2个月，3周，4天，16小时，15分钟，22秒前
下面的代码更改做了我所需要的。 当然，道具先去xdebug。 希望别人可能会觉得它有用：
function fTime($time, $gran=-1) { $d[0] = array(1,"second"); $d[1] = array(60,"minute"); $d[2] = array(3600,"hour"); $d[3] = array(86400,"day"); $d[4] = array(604800,"week"); $d[5] = array(2592000,"month"); $d[6] = array(31104000,"year"); $w = array(); $return = ""; $now = time(); $diff = ($now-$time); $secondsLeft = $diff; $stopat = 0; for($i=6;$i>$gran;$i--) { $w[$i] = intval($secondsLeft/$d[$i][0]); $secondsLeft -= ($w[$i]*$d[$i][0]); if($w[$i]!=0) { $return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." "; switch ($i) { case 6: // shows years and months if ($stopat==0) { $stopat=5; } break; case 5: // shows months and weeks if ($stopat==0) { $stopat=4; } break; case 4: // shows weeks and days if ($stopat==0) { $stopat=3; } break; case 3: // shows days and hours if ($stopat==0) { $stopat=2; } break; case 2: // shows hours and minutes if ($stopat==0) { $stopat=1; } break; case 1: // shows minutes and seconds if granularity is not set higher break; } if ($i===$stopat) { break 0; } } } $return .= ($diff>0)?"ago":"left"; return $return; }
马库斯
我需要一个给我的结果如下，所以我写了我自己的。 希望这会帮助别人。
用法示例：
$datetime = "2014-08-13 12:52:48"; echo getRelativeTime($datetime); //10 hours ago echo getRelativeTime($datetime, 1); //10 hours ago echo getRelativeTime($datetime, 2); //10 hours and 50 minutes ago echo getRelativeTime($datetime, 3); //10 hours, 50 minutes and 50 seconds ago echo getRelativeTime($datetime, 4); //10 hours, 50 minutes and 50 seconds ago
码：
public function getRelativeTime($datetime, $depth=1) { $units = array( "year"=>31104000, "month"=>2592000, "week"=>604800, "day"=>86400, "hour"=>3600, "minute"=>60, "second"=>1 ); $plural = "s"; $conjugator = " and "; $separator = ", "; $suffix1 = " ago"; $suffix2 = " left"; $now = "now"; $empty = ""; # DO NOT EDIT BELOW $timediff = time()-strtotime($datetime); if ($timediff == 0) return $now; if ($depth < 1) return $empty; $max_depth = count($units); $remainder = abs($timediff); $output = ""; $count_depth = 0; $fix_depth = true; foreach ($units as $unit=>$value) { if ($remainder>$value && $depth-->0) { if ($fix_depth) { $max_depth -= ++$count_depth; if ($depth>=$max_depth) $depth=$max_depth; $fix_depth = false; } $u = (int)($remainder/$value); $remainder %= $value; $pluralise = $u>1?$plural:$empty; $separate = $remainder==0||$depth==0?$empty: ($depth==1?$conjugator:$separator); $output .= "{$u} {$unit}{$pluralise}{$separate}"; } $count_depth++; } return $output.($timediff<0?$suffix2:$suffix1); }
你可以通过packagist使用Carbon，简直太棒了:) https://github.com/briannesbitt/Carbon#api-humandiff
为什么不采用drupal的方式呢？ – http://api.drupal.org/api/drupal/includes%21common.inc/function/format_interval/7
<?php function format_interval($interval, $granularity = 2, $langcode = NULL) { $units = array( '1 year|@count years' => 31536000, '1 month|@count months' => 2592000, '1 week|@count weeks' => 604800, '1 day|@count days' => 86400, '1 hour|@count hours' => 3600, '1 min|@count min' => 60, '1 sec|@count sec' => 1, ); $output = ''; foreach ($units as $key => $value) { $key = explode('|', $key); if ($interval >= $value) { $output .= ($output ? ' ' : '') . format_plural(floor($interval / $value), $key[0], $key[1], array(), array('langcode' => $langcode)); $interval %= $value; $granularity--; } if ($granularity == 0) { break; } } return $output ? $output : t('0 sec', array(), array('langcode' => $langcode)); } ?>
你可能不需要replacet（），你可以很容易地为format_plural做你自己的事情，因为你（可能）不需要支持多种语言。 http://api.drupal.org/api/drupal/includes%21common.inc/function/format_plural/7
以下是我过去使用的东西：
function zdateRelative($date) { $diff = time() - $date; $periods[] = [60, 1, '%s seconds ago', 'a second ago']; $periods[] = [60*100, 60, '%s minutes ago', 'one minute ago']; $periods[] = [3600*70, 3600, '%s hours ago', 'an hour ago']; $periods[] = [3600*24*10, 3600*24, '%s days ago', 'yesterday']; $periods[] = [3600*24*30, 3600*24*7, '%s weeks ago', 'one week ago']; $periods[] = [3600*24*30*30, 3600*24*30, '%s months ago', 'last month']; $periods[] = [INF, 3600*24*265, '%s years ago', 'last year']; foreach ($periods as $period) { if ($diff > $period[0]) continue; $diff = floor($diff / $period[1]); return sprintf($diff > 1 ? $period[2] : $period[3], $diff); } }
