如何使用PHP cURL发布JSON数据？

这是我的代码，

$url = 'url_to_post'; $data = array("first_name" => "First name","last_name" => "last name","email"=>"[e-mail]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) ); $data_string = json_encode($data); $ch=curl_init($url); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string)); curl_setopt($ch, CURLOPT_HEADER, true); curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json', 'Content-Length: ' . strlen($data_string)) ); $result = curl_exec($ch); curl_close($ch); 

而在其他页面上，我正在检索发布数据。

  print_r ($_POST); 

输出是

 HTTP/1.1 200 OK Date: Mon, 18 Jun 2012 07:58:11 GMT Server: Apache X-Powered-By: PHP/5.3.6 Vary: Accept-Encoding Connection: close Content-Type: text/html Array ( ) 

所以，即使在我自己的服务器上，我也没有得到正确的数据，这是空的数组。 我想要在http://docs.shopify.com/api/customer#create中使用json实现REST

Answer 1

你错误地发布了json – 但即使它是正确的，你也不能使用print_r($_POST)来testing（请阅读原因 ）。 相反，在第二页上，您可以使用file_get_contents("php://input")来获取传入的请求，该文件将包含POST的json 。 要以更具可读性的格式查看收到的数据，请尝试以下操作：

 echo '<pre>'.print_r(json_decode(file_get_contents("php://input")),1).'</pre>'; 

在你的代码中，你指的是Content-Type:application/json ，但是你不是对所有的POST数据进行json编码的 – 只有“customer”POST字段的值。 相反，做这样的事情：

 $ch = curl_init( $url ); # Setup request to send json via POST. $payload = json_encode( array( "customer"=> $data ) ); curl_setopt( $ch, CURLOPT_POSTFIELDS, $payload ); curl_setopt( $ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json')); # Return response instead of printing. curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true ); # Send request. $result = curl_exec($ch); curl_close($ch); # Print response. echo "<pre>$result</pre>"; 

旁注：您可能会从使用第三方库中受益，而不是直接与Shopify API进行交互。

Answer 2

更换

 curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string)); 

有：

 $data_string = json_encode(array("customer"=>$data)); //Send blindly the json-encoded string. //The server, IMO, expects the body of the HTTP request to be in JSON curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string); 

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我没有得到你的意思是“其他网页”，我希望它是在'url_to_post'页面。 如果该页面是用PHP编写的，那么您刚刚发布的JSON将按照以下方式阅读：

 $jsonStr = file_get_contents("php://input"); //read the HTTP body. $json = json_decode($jsonStr); 

Answer 3

试试这个例子。

 <?php $url = 'http://localhost/test/page2.php'; $data = array("first_name" => "First name","last_name" => "last name","email"=>"[e-mail]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) ); $ch=curl_init($url); $data_string = urlencode(json_encode($data)); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POSTFIELDS, array("customer"=>$data_string)); $result = curl_exec($ch); curl_close($ch); echo $result; ?> 

你的page2.php代码

 <?php $datastring = $_POST['customer']; $data = json_decode( urldecode( $datastring)); ?> 

Answer 4

尝试像这样：

 $url = 'url_to_post'; // this is only part of the data you need to sen $customer_data = array("first_name" => "First name","last_name" => "last name","email"=>"[e-mail]","addresses" => array ("address1" => "some address" ,"city" => "city","country" => "CA", "first_name" => "Mother","last_name" => "Lastnameson","phone" => "555-1212", "province" => "ON", "zip" => "123 ABC" ) ); // As per your API, the customer data should be structured this way $data = array("customer" => $customer_data); // And then encoded as a json string $data_string = json_encode($data); $ch=curl_init($url); curl_setopt_array($ch, array( CURLOPT_POST => true, CURLOPT_POSTFIELDS => $data_string, CURLOPT_HEADER => true, CURLOPT_HTTPHEADER => array('Content-Type:application/json', 'Content-Length: ' . strlen($data_string))) )); $result = curl_exec($ch); curl_close($ch); 

你忘记的关键是对你的数据进行json编码。 但是你也可能会发现使用curl_setopt_array通过传递一个数组来立即设置所有curl选项是很方便的。