最好的方法来parsingURLstring来获取键的值？
我需要parsing一个这样的URLstring：
&ad_eurl=http://www.youtube.com/video/4bL4FI1Gz6s&hl=it_IT&iv_logging_level=3&ad_flags=0&endscreen_module=http://s.ytimg.com/yt/swfbin/endscreen-vfl6o3XZn.swf&cid=241&cust_gender=1&avg_rating=4.82280613104 我需要将NSString分成像cid=241和&avg_rating=4.82280613104 。 我一直在用substringWithRange:这样做substringWithRange:但是这些值以随机的顺序返回，所以弄乱了它。 有没有任何类，允许轻松parsing，你可以基本上转换为NSDictionary能够读取一个键的值（例如ValueForKey： cid应该返回241 ）。 或者是只有另一种更简单的方法来parsing它比使用NSMakeRange获取子string？
我会创build一个字典，获取一个键/值对的数组
NSMutableDictionary *queryStringDictionary = [[NSMutableDictionary alloc] init]; NSArray *urlComponents = [urlString componentsSeparatedByString:@"&"];
然后填充字典：
for (NSString *keyValuePair in urlComponents) { NSArray *pairComponents = [keyValuePair componentsSeparatedByString:@"="]; NSString *key = [[pairComponents firstObject] stringByRemovingPercentEncoding]; NSString *value = [[pairComponents lastObject] stringByRemovingPercentEncoding]; [queryStringDictionary setObject:value forKey:key]; }
你可以用查询
[queryStringDictionary objectForKey:@"ad_eurl"];
这是未经testing的，你应该做更多的错误testing。
我也通过https://stackoverflow.com/a/26406478/215748回答了这个问题。;
您可以在URLComponents使用queryItems 。
获取此属性的值时，NSURLComponents类将parsing查询string，并按照它们在原始查询string中的显示顺序返回一个NSURLQueryItem对象数组，每个对象表示一个键 – 值对。
Swift 3
let url = "http://example.com?param1=value1¶m2=param2" let queryItems = URLComponents(string: url)?.queryItems let param1 = queryItems?.filter({$0.name == "param1"}).first print(param1?.value)
Swift 2.3
使用NSURLComponents而不是URLComponents 。
目标C
使用NSURLComponents 。
NSURLComponents *urlComponents = [NSURLComponents componentsWithURL:url resolvingAgainstBaseURL:NO]; NSArray *queryItems = urlComponents.queryItems; NSString *param1 = [self valueForKey:@"param1" fromQueryItems:queryItems]; NSLog(@"%@", param1); … - (NSString *)valueForKey:(NSString *)key fromQueryItems:(NSArray *)queryItems { NSPredicate *predicate = [NSPredicate predicateWithFormat:@"name=%@", key]; NSURLQueryItem *queryItem = [[queryItems filteredArrayUsingPredicate:predicate] firstObject]; return queryItem.value; }
我有点晚了，但直到现在提供的答案没有按需要工作。 你可以使用这个代码片段：
NSMutableDictionary *queryStrings = [[NSMutableDictionary alloc] init]; for (NSString *qs in [url.query componentsSeparatedByString:@"&"]) { // Get the parameter name NSString *key = [[qs componentsSeparatedByString:@"="] objectAtIndex:0]; // Get the parameter value NSString *value = [[qs componentsSeparatedByString:@"="] objectAtIndex:1]; value = [value stringByReplacingOccurrencesOfString:@"+" withString:@" "]; value = [value stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; queryStrings[key] = value; }
其中， url是您要parsing的url。 在queryStrings可变字典中，所有查询string都已转义。
编辑 ：迅捷版本：
var queryStrings = [String: String]() if let query = url.query { for qs in query.componentsSeparatedByString("&") { // Get the parameter name let key = qs.componentsSeparatedByString("=")[0] // Get the parameter value var value = qs.componentsSeparatedByString("=")[1] value = value.stringByReplacingOccurrencesOfString("+", withString: " ") value = value.stringByReplacingPercentEscapesUsingEncoding(NSUTF8StringEncoding)! queryStrings[key] = value } }
对于使用NSURLComponents iOS8和更高NSURLComponents ：
+(NSDictionary<NSString *, NSString *> *)queryParametersFromURL:(NSURL *)url { NSURLComponents *urlComponents = [NSURLComponents componentsWithURL:url resolvingAgainstBaseURL:NO]; NSMutableDictionary<NSString *, NSString *> *queryParams = [NSMutableDictionary<NSString *, NSString *> new]; for (NSURLQueryItem *queryItem in [urlComponents queryItems]) { if (queryItem.value == nil) { continue; } [queryParams setObject:queryItem.value forKey:queryItem.name]; } return queryParams; }
对于以下的iOS 8：
+(NSDictionary<NSString *, NSString *> *)queryParametersFromURL:(NSURL *)url NSMutableDictionary<NSString *, NSString *> * parameters = [NSMutableDictionary<NSString *, NSString *> new]; [self enumerateKeyValuePairsFromQueryString:url.query completionblock:^(NSString *key, NSString *value) { parameters[key] = value; }]; return parameters.copy; } - (void)enumerateKeyValuePairsFromQueryString:(NSString *)queryString completionBlock:(void (^) (NSString *key, NSString *value))block { if (queryString.length == 0) { return; } NSArray *keyValuePairs = [queryString componentsSeparatedByString:@"&"]; for (NSString *pair in keyValuePairs) { NSRange range = [pair rangeOfString:@"="]; NSString *key = nil; NSString *value = nil; if (range.location == NSNotFound) { key = pair; value = @""; } else { key = [pair substringToIndex:range.location]; value = [pair substringFromIndex:(range.location + range.length)]; } key = [self decodedStringFromString:key]; key = key ?: @""; value = [self decodedStringFromString:value]; value = value ?: @""; block(key, value); } } + (NSString *)decodedStringFromString:(NSString *)string { NSString *input = shouldDecodePlusSymbols ? [string stringByReplacingOccurrencesOfString:@"+" withString:@" " options:NSLiteralSearch range:NSMakeRange(0, string.length)] : string; return [input stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; }
如果你想快速做同样的事情，你可以使用扩展名。
extension NSURL { func queryDictionary() -> [String:String] { let components = self.query?.componentsSeparatedByString("&") var dictionary = [String:String]() for pairs in components ?? [] { let pair = pairs.componentsSeparatedByString("=") if pair.count == 2 { dictionary[pair[0]] = pair[1] } } return dictionary } }
如果你使用的是NSURLComponents ，下面简要的扩展也会做到这一点：
extension NSURLComponents { func getQueryStringParameter(name: String) -> String? { return (self.queryItems? as [NSURLQueryItem]) .filter({ (item) in item.name == name }).first? .value() } }
-(NSArray *)getDataOfQueryString:(NSString *)url{ NSArray *strURLParse = [url componentsSeparatedByString:@"?"]; NSMutableArray *arrQueryStringData = [[NSMutableArray alloc] init]; if ([strURLParse count] < 2) { return arrQueryStringData; } NSArray *arrQueryString = [[strURLParse objectAtIndex:1] componentsSeparatedByString:@"&"]; for (int i=0; i < [arrQueryString count]; i++) { NSMutableDictionary *dicQueryStringElement = [[NSMutableDictionary alloc]init]; NSArray *arrElement = [[arrQueryString objectAtIndex:i] componentsSeparatedByString:@"="]; if ([arrElement count] == 2) { [dicQueryStringElement setObject:[arrElement objectAtIndex:1] forKey:[arrElement objectAtIndex:0]]; } [arrQueryStringData addObject:dicQueryStringElement]; } return arrQueryStringData; }
你这个函数只是传递URL，你会得到查询string的所有元素。
这个代码有三种情况
1. http://www.youtube.com/watch?v=VWsl7C-y7EI&feature=youtu.be 2. http://youtu.be/lOvcFqQyaDY
3. http://www.youtube.com/watch?v=VWsl7C-y7EI
NSArray *arr = [youtubeurl componentsSeparatedByString:@"v="]; NSString *youtubeID; if([arr count]>0) { if([arr count]==1){ youtubeID= [[youtubeurl componentsSeparatedByString:@"/"] lastObject]; } else{ NSArray *urlComponents = [[arr objectAtIndex:1] componentsSeparatedByString:@"&"]; youtubeID=[urlComponents objectAtIndex:0]; } }
从iOS 8开始，您可以直接在NSURLQueryItem上使用属性name和value 。
例如，如何parsingURL并获取parsing对中的键的特定值。
NSURLComponents *urlComponents = [NSURLComponents componentsWithURL:@"someURL" resolvingAgainstBaseURL:false]; NSArray *queryItems = urlComponents.queryItems; NSMutableArray *someIDs = [NSMutableArray new]; for (NSURLQueryItem *item in queryItems) { if ([item.name isEqualToString:@"someKey"]) { [someIDs addObject:item.value]; } } NSLog(@"%@", someIDs);
作为全function：
+ (NSString *)getQueryComponentWithName:(NSString *)name fromURL:(NSURL *)url{ NSString *component = nil; if (url) { NSString *query = url.query; NSMutableDictionary *queryStringDictionary = [NSMutableDictionary dictionary]; NSArray *urlComponents = [query componentsSeparatedByString:@"&"]; for (NSString *keyValuePair in urlComponents){ NSArray *pairComponents = [keyValuePair componentsSeparatedByString:@"="]; NSString *key = [[pairComponents firstObject] stringByRemovingPercentEncoding]; NSString *value = [[pairComponents lastObject] stringByRemovingPercentEncoding]; [queryStringDictionary setObject:value forKey:key]; } component = [queryStringDictionary objectForKey:name]; } return component; } [self getQueryComponentWithName:@"example" fromURL:[NSURL URLWithString:@"https://google.es/?example=test"]];
查询属性NSURL将给出查询string。 然后你可以使用componentsSeparatedByStringparsing查询string
NSArray *parameters = [[url query] componentsSeparatedByString:@"&"]; NSMutableDictionary *keyValuePairs = [NSMutableDictionary dictionary]; for (NSString *eachParam in parameters) { NSArray *QryParts = [eachParam componentsSeparatedByString:@"="]; if ( [QryParts count] == 2 ) { keyValuePairs[QryParts[0]] = QryParts[1]; } else { keyValuePairs[QryParts[0]] = QryParts[0]; } } NSString * name = [keyValuePairs valueForKey:@"name"]; NSString * username = [keyValuePairs valueForKey:@"username"];
- (NSString *)getLoginTokenFromUrl:(NSString *)urlString { NSURL *url = [NSURL URLWithString:urlString]; NSArray *queryStrings = [url.query componentsSeparatedByString:@"&"]; NSMutableDictionary *queryParams = [[NSMutableDictionary alloc] init]; for (NSString *qs in queryStrings) { // Get the parameter name NSArray *components = [qs componentsSeparatedByString:@"="]; NSString *key = [components objectAtIndex:0]; // Get the parameter value NSString *value; if (components.count > 1) { value = [components objectAtIndex:1]; } else { value = @""; } value = [value stringByReplacingOccurrencesOfString:@"+" withString:@" "]; value = [value stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; queryParams[key] = value; } return [queryParams objectForKey:@"login_token"]; }
Swift 2方法：
extension NSURL { var queryDictionary: [String: String] { var queryDictionary = [String: String]() guard let components = NSURLComponents(URL: self, resolvingAgainstBaseURL: false), queryItems = components.queryItems else { return queryDictionary } queryItems.forEach { queryDictionary[$0.name] = $0.value } return queryDictionary } }
下载Gist
在URL上以Swift 3扩展的forms来解决这个问题
extension URL { func value(for paramater: String) -> String? { let queryItems = URLComponents(string: self.absoluteString)?.queryItems let queryItem = queryItems?.filter({$0.name == paramater}).first let value = queryItem?.value return value } }
要旨
