如何在Oracle中获得主键列？

我需要获取主键列的名称。

在input中，我只有表名。

Answer 1

SELECT cols.table_name, cols.column_name, cols.position, cons.status, cons.owner FROM all_constraints cons, all_cons_columns cols WHERE cols.table_name = 'TABLE_NAME' AND cons.constraint_type = 'P' AND cons.constraint_name = cols.constraint_name AND cons.owner = cols.owner ORDER BY cols.table_name, cols.position; 

请确保“TABLE_NAME”是大写，因为Oracle以大写forms存储表名。

Answer 2

和“Richie”的答案一样，但更简洁一些。

1. 仅查询用户约束

    SELECT column_name FROM all_cons_columns WHERE constraint_name = ( SELECT constraint_name FROM user_constraints WHERE UPPER(table_name) = UPPER('tableName') AND CONSTRAINT_TYPE = 'P' ); 

2. 查询所有约束

    SELECT column_name FROM all_cons_columns WHERE constraint_name = ( SELECT constraint_name FROM all_constraints WHERE UPPER(table_name) = UPPER('tableName') AND CONSTRAINT_TYPE = 'P' ); 

Answer 3

 Select constraint_name,constraint_type from user_constraints where table_name** **= 'TABLE_NAME' ; 

（这将列出主键然后）

 Select column_name,position from user_cons_cloumns where constraint_name='PK_XYZ'; 

（这会给你的列，这里PK_XYZ是主键名）

Answer 4

将下面的脚本保存为findPK.sql。

 set verify off accept TABLE_NAME char prompt 'Table name>' SELECT cols.column_name FROM all_constraints cons NATURAL JOIN all_cons_columns cols WHERE cons.constraint_type = 'P' AND table_name = UPPER('&TABLE_NAME'); 

然后可以使用它

 @findPK 

Answer 5

试试这个代码在这里我创build了一个表，用于获取oracle中的主键列，称为testing然后查询

 create table test ( id int, name varchar2(20), city varchar2(20), phone int, constraint pk_id_name_city primary key (id,name,city) ); SELECT cols.table_name, cols.column_name, cols.position, cons.status, cons.owner FROM all_constraints cons, all_cons_columns cols WHERE cols.table_name = 'TEST' AND cons.constraint_type = 'P' AND cons.constraint_name = cols.constraint_name AND cons.owner = cols.owner ORDER BY cols.table_name, cols.position;