GROUP_CONCAT ORDER BY

我有一个表如：

+-----------+-------+------------+ | client_id | views | percentage | +-----------+-------+------------+ | 1 | 6 | 20 | | 1 | 4 | 55 | | 1 | 9 | 56 | | 1 | 2 | 67 | | 1 | 7 | 80 | | 1 | 5 | 66 | | 1 | 3 | 33 | | 1 | 8 | 34 | | 1 | 1 | 52 | 

我试过group_concat ：

 SELECT li.client_id, group_concat(li.views) AS views, group_concat(li.percentage) FROM li GROUP BY client_id; +-----------+-------------------+-----------------------------+ | client_id | views | group_concat(li.percentage) | +-----------+-------------------+-----------------------------+ | 1 | 6,4,9,2,7,5,3,8,1 | 20,55,56,67,80,66,33,34,52 | +-----------+-------------------+-----------------------------+ 

但是我想按顺序得到意见，比如：

 +-----------+-------------------+----------------------------+ | client_id | views | percentage | +-----------+-------------------+----------------------------+ | 1 | 1,2,3,4,5,6,7,8,9 | 52,67,33,55,66,20,80,34,56 | +-----------+-------------------+----------------------------+ 

Answer 1

您可以通过这种方式在GROUP_CONCAT函数中使用ORDER BY ：

 SELECT li.client_id, group_concat(li.percentage ORDER BY li.views ASC) AS views, group_concat(li.percentage ORDER BY li.percentage ASC) FROM li GROUP BY client_id 

Answer 2

group_concat支持自己的order by子句

http://mahmudahsan.wordpress.com/2008/08/27/mysql-the-group_concat-function/

所以你应该可以写：

 SELECT li.clientid, group_concat(li.views order by views) AS views, group_concat(li.percentage order by percentage) FROM table_views GROUP BY client_id 

Answer 3

尝试

 SELECT li.clientid, group_concat(li.views ORDER BY li.views) AS views, group_concat(li.percentage ORDER BY li.percentage) FROM table_views li GROUP BY client_id 

http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function%5Fgroup-concat

Answer 4

在IMPALA，没有在GROUP_CONCAT中的订单可能是有问题的，在编码公司。 我们有一些解决方法（我们需要Rax / Impala）。 如果您需要在IMPALA中使用ORDER BY子句的GROUP_CONCAT结果，请查看以下博客文章： http : //raxdb.com/blog/sorting-by-regex/