两个date之间的SQL时间差异导致hh:mm:ss

我在计算两个date之间的时间差时遇到一些困难。

我想要的是,我有两个date说

@StartDate = '10/01/2012 08:40:18.000' @EndDate='10/04/2012 09:52:48.000' 

所以hh:mm:ssforms的两个date之间的差别是72:42:30

我怎样才能得到这个结果在T-SQL查询?

13 Solutions collect form web for “两个date之间的SQL时间差异导致hh:mm:ss”

 declare @StartDate datetime, @EndDate datetime select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000' select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60)) as [hh:mm:ss] 

这个查询对你有帮助。

最短的代码是:

 Select CAST((@EndDateTime-@StartDateTime) as time(0)) '[hh:mm:ss]' 

虽然可能不是最有效的,但这将工作:

 declare @StartDate datetime, @EndDate datetime select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000' select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60)) 

如果你可以运行两个select,那么这将是更好的,因为你只做过一次:

 declare @StartDate datetime, @EndDate datetime select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000' declare @Sec BIGINT select @Sec = DateDiff(s, @startDate, @EndDate) select convert(varchar(5),@sec/3600)+':'+convert(varchar(5),@sec%3600/60)+':'+convert(varchar(5),(@sec%60)) 

如果你不反对隐式types转换,我会提供这个替代解决scheme。 更好的格式化可读性更强吗? 你是法官。

 DECLARE @StartDate datetime = '10/01/2012 08:40:18.000' ,@EndDate datetime = '10/04/2012 09:52:48.000' SELECT STR(ss/3600, 5) + ':' + RIGHT('0' + LTRIM(ss%3600/60), 2) + ':' + RIGHT('0' + LTRIM(ss%60), 2) AS [hh:mm:ss] FROM (VALUES(DATEDIFF(s, @StartDate, @EndDate))) seconds (ss) 
 DECLARE @dt1 datetime='2012/06/13 08:11:12', @dt2 datetime='2012/06/12 02:11:12' SELECT CAST((@dt2-@dt1) as time(0)) 

看看这些。 我没有使用更多的括号来保持它的可读性,所以记住在加或减之前进行乘法运算。

下面两个回报:

 hr mins sec timediff 73 12 30 73:12:30 

这是写入不使用子查询,是最可读和可以理解的:

 declare @StartDate datetime, @EndDate datetime set @StartDate = '10/01/2012 08:40:18.000' set @EndDate = '10/04/2012 09:52:48.000' select datediff(hour, @StartDate, @EndDate) hr, datediff(minute, @StartDate, @EndDate) - datediff(hour, @StartDate, @EndDate) * 60 mins, datediff(second, @StartDate, @EndDate) - (datediff(minute, @StartDate, @EndDate) * 60) sec, cast(datediff(hour, @StartDate, @EndDate) as varchar)+':'+ cast(datediff(minute, @StartDate, @EndDate) - datediff(hour, @StartDate, @EndDate) * 60 as varchar)+':'+ cast(datediff(second, @StartDate, @EndDate) - (datediff(minute, @StartDate, @EndDate) * 60) as varchar) timediff 

如果你有很多的数据,这个版本的性能会更好。 它需要一个子查询。

 declare @StartDate datetime, @EndDate datetime set @StartDate = '10/01/2012 08:40:18.000' set @EndDate = '10/04/2012 09:52:48.000' select s.seconds / 3600 hrs, s.seconds / 60 - (seconds / 3600 ) * 60 mins, s.seconds - (s.seconds / 60) * 60 seconds, cast(s.seconds / 3600 as varchar) + ':' + cast((s.seconds / 60 - (seconds / 3600 ) * 60) as varchar) + ':' + cast((s.seconds - (s.seconds / 60) * 60) as varchar) timediff from (select datediff(second, @StartDate, @EndDate) as seconds) s 

今天我遇到了这个post,因为我试图收集位于不同表格中的字段之间的时差。 这是这种努力的工作准则。 (在sql 2010中testing)请记住,我的原始查询共同join了一个公共的keyfield上的6个表,在下面的代码中,我已经删除了其他表,以免引起读者的混淆。

查询的目的是计算CreatedUTC&BackupUTCvariables之间的差异,其中差异以天表示,并且该字段被称为“DaysActive”。

 declare @CreatedUTC datetime declare @BackupUtc datetime SELECT TOP 500 table02.Column_CreatedUTC AS DeviceCreated, CAST(DATEDIFF(day, table02.Column_CreatedUTC, table03.Column_EndDateUTC) AS nvarchar(5))+ ' Days' As DaysActive, table03.Column_EndDateUTC AS LastCompleteBackup FROM Operations.table01 AS table01 LEFT OUTER JOIN dbo.table02 AS table02 ON table02.Column_KeyField = table01.Column_KeyField LEFT OUTER JOIN dbo.table03 AS table03 ON table01.Column_KeyField = table03.Column_KeyField Where table03.Column_EndDateUTC > dateadd(hour, -24, getutcdate()) --Gathers records with an end date in the last 24 hours AND table02.[Column_CreatedUTC] = COALESCE(@CreatedUTC, table02.[Column_CreatedUTC]) AND table03.[Column_EndDateUTC] = COALESCE(@BackupUTC, table03.[Column_EndDateUTC]) GROUP BY table03.Column_EndDateUTC, table02.Column_CreatedUTC ORDER BY table02.Column_CreatedUTC ASC, DaysActive, table03.Column_EndDateUTC DESC 

产出如下:

 [DeviceCreated]..[DaysActive]..[LastCompleteBackup] --------------------------------------------------------- [2/13/12 16:04]..[463 Days]....[5/21/13 12:14] [2/12/13 22:37]..[97 Days].....[5/20/13 22:10] 

这是一个脚本写复制然后写在你的脚本文件,并改变你的重新调整的领域,并出去

 DECLARE @Sdate DATETIME, @Edate DATETIME, @Timediff VARCHAR(100) SELECT @Sdate = '02/12/2014 08:40:18.000',@Edate='02/13/2014 09:52:48.000' SET @Timediff=DATEDIFF(s, @Sdate, @Edate) SELECT CONVERT(VARCHAR(5),@Timediff/3600)+':'+convert(varchar(5),@Timediff%3600/60)+':'+convert(varchar(5),@Timediff%60) AS TimeDiff 
 DECLARE @StartDate datetime = '10/01/2012 08:40:18.000' ,@EndDate datetime = '10/10/2012 09:52:48.000' ,@DaysDifferent int = 0 ,@Sec BIGINT select @Sec = DateDiff(s, @StartDate, @EndDate) IF (DATEDIFF(day, @StartDate, @EndDate) > 0) BEGIN select @DaysDifferent = DATEDIFF(day, @StartDate, @EndDate) select @Sec = @Sec - ( @DaysDifferent * 86400 ) SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss] END ELSE BEGIN SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss] END ---------------------------------------------------------------------------------- dd HH:MM:SS 9d 1:12:30 
 declare @StartDate datetime, @EndDate datetime select @StartDate = '2016-05-04 10:23:41.083',@EndDate='2016-05-04 10:25:26.053' select CAST(DateDiff(MI, @startDate, @EndDate)/60 AS varchar)+':'+Cast(DateDiff(MI, @startDate, @EndDate)%60 AS varchar)+':'+cast(DateDiff(s, @startDate, @EndDate)%60 AS varchar) as [hh:mm:ss] 

这也会帮助你

我喜欢把它变成一个函数,所以它变得可重用,你的查询变得更容易阅读:

 --get the difference between two datetimes in the format: 'h:m:s' CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME) RETURNS VARCHAR(10) AS BEGIN DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate) DECLARE @difference VARCHAR(10) = CONVERT(VARCHAR(4), @seconds / 3600) + ':' + CONVERT(VARCHAR(2), @seconds % 3600 / 60) + ':' + CONVERT(VARCHAR(2), @seconds % 60) RETURN @difference END 

用法:

 DECLARE @StartDate DATETIME = '10/01/2012 08:40:18.000' DECLARE @endDate DATETIME = '10/04/2012 09:52:48.000' SELECT dbo.getDateDiff(@startDate, @endDate) AS DateDifference 

结果:

  DateDifference 1 73:12:30 

如果添加填充,则读取结果也更容易,因此格式始终为hh:mm:ss 。 例如,以下是在SQL Server 2012或更高版本中如何执行此操作的方法:

 --get the difference between two datetimes in the format: 'hh:mm:ss' CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME) RETURNS VARCHAR(10) AS BEGIN DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate) DECLARE @difference VARCHAR(10) = FORMAT(@seconds / 3600), '00') + ':' + FORMAT(@seconds % 3600 / 60, '00') + ':' + FORMAT(@seconds % 60, '00') RETURN @difference END 

请注意,如果长度超过2位,则不会剪辑小时。 所以1小时显示为01 100:00:00 01:00:00小时显示为100:00:00

声明@StartDatedate时间,@EndDatedate时间

 set @StartDate = '10/01/2012 08:40:18.000' set @EndDate = '10/04/2012 09:52:48.000' SELECT CONVERT(CHAR(8), CAST(CONVERT(varchar(23),@EndDate,121) AS DATETIME) -CAST(CONVERT(varchar(23),@StartDate,121)AS DATETIME),8) AS TimeDiff 
 declare @StartDate datetime; declare @EndDate datetime; select @StartDate = '10/01/2012 08:40:18.000'; select @EndDate='10/04/2012 09:52:48.000'; select cast(datediff(hour,@StartDate,@EndDate) as varchar(10)) + left(right(cast(cast(cast((@EndDate-@StartDate) as datetime) as time) as varchar(16)),14),6) 
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