如何列出两个date之间的所有date
我想在SQL Server存储过程中的两个date之间列出date。
例如：
Date1: 2015-05-28 Date2: 2015-05-31 结果：
2015-05-29 2015-05-30
如何计算两个给定date之间的所有date？
问候，
您可以使用数字表格：
DECLARE @Date1 DATE, @Date2 DATE SET @Date1 = '20150528' SET @Date2 = '20150531' SELECT DATEADD(DAY,number+1,@Date1) [Date] FROM master..spt_values WHERE type = 'P' AND DATEADD(DAY,number+1,@Date1) < @Date2
结果：
╔════════════╗ ║ Date ║ ╠════════════╣ ║ 2015-05-29 ║ ║ 2015-05-30 ║ ╚════════════╝
用这个，
DECLARE @start_date DATETIME = '2015-02-12 00:00:00.000'; DECLARE @end_date DATETIME = '2015-02-13 00:00:00.000'; WITH AllDays AS ( SELECT @start_date AS [Date], 1 AS [level] UNION ALL SELECT DATEADD(DAY, 1, [Date]), [level] + 1 FROM AllDays WHERE [Date] < @end_date ) SELECT [Date], [level] FROM AllDays OPTION (MAXRECURSION 0)
传递@start_date和@end_date作为SP参数。
结果：
Date level ----------------------- ----------- 2015-02-12 00:00:00.000 1 2015-02-13 00:00:00.000 2 (2 row(s) affected)
创build一个类似于以下内容的存储过程：
declare @startDate date; declare @endDate date; select @startDate = '20150528'; select @endDate = '20150531'; with dateRange as ( select dt = dateadd(dd, 1, @startDate) where dateadd(dd, 1, @startDate) < @endDate union all select dateadd(dd, 1, dt) from dateRange where dateadd(dd, 1, dt) < @endDate ) select * from dateRange
SQL小提琴与演示 。
或者更好的是创build一个日历表，并从中select。
我做了一个日历，使用：
http://social.technet.microsoft.com/wiki/contents/articles/22776.t-sql-calendar-table.aspx
然后一个存储过程传递两个date，这就是所有：
USE DB_NAME; GO CREATE PROCEDURE [dbo].[USP_LISTAR_RANGO_FECHAS] @FEC_INICIO date, @FEC_FIN date AS Select Date from CALENDARIO where Date BETWEEN @FEC_INICIO AND @FEC_FIN;
您可以创build一个存储过程传递两个date
CREATE PROCEDURE SELECTALLDATES ( @StartDate as date, @EndDate as date ) AS Declare @Current as date = DATEADD(DD, 1, @BeginDate); Create table #tmpDates (displayDate date) WHILE @Current < @EndDate BEGIN insert into #tmpDates VALUES(@Current); set @Current = DATEADD(DD, 1, @Current) -- add 1 to current day END Select * from #tmpDates drop table #tmpDates
