如何打开手机设置，当一个button被点击ios

我试图在应用程序中实现一个function，当互联网连接不可用时显示警报。 该警报有两个行动确定和设置，每当用户点击设置，我想要带他们到手机设置编程。

我正在使用Swift和Xcode-Beta

使用UIApplicationOpenSettingsURLString

Swift 3更新 

 override func viewDidAppear(_ animated: Bool) { let alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle: .alert) let settingsAction = UIAlertAction(title: "Settings", style: .default) { (_) -> Void in guard let settingsUrl = URL(string: UIApplicationOpenSettingsURLString) else { return } if UIApplication.shared.canOpenURL(settingsUrl) { UIApplication.shared.open(settingsUrl, completionHandler: { (success) in print("Settings opened: \(success)") // Prints true }) } } alertController.addAction(settingsAction) let cancelAction = UIAlertAction(title: "Cancel", style: .default, handler: nil) alertController.addAction(cancelAction) present(alertController, animated: true, completion: nil) }

Swift 2.x 

 override func viewDidAppear(animated: Bool) { var alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle: .Alert) var settingsAction = UIAlertAction(title: "Settings", style: .Default) { (_) -> Void in let settingsUrl = NSURL(string: UIApplicationOpenSettingsURLString) if let url = settingsUrl { UIApplication.sharedApplication().openURL(url) } } var cancelAction = UIAlertAction(title: "Cancel", style: .Default, handler: nil) alertController.addAction(settingsAction) alertController.addAction(cancelAction) presentViewController(alertController, animated: true, completion: nil) }

有时候我们想把用户带到除了我们的应用程序设置之外的设置。 以下方法将帮助您实现：

注意：此方法适用于所有版本的iOS

首先在你的项目中configurationURL Schemes。 你会在Target – > Info – > URL Scheme中find它。 点击+button并在URL Schemes中input前缀

在这里输入图像描述

迅速 

 UIApplication.sharedApplication().openURL(NSURL(string:"prefs:root=General")!)

Swift 3 

 UIApplication.shared.open(URL(string:"App-Prefs:root=General")!, options: [:], completionHandler: nil)

Objective-C的 

 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=General"]];

以下是所有可用的url

  • 首选项：根=通用及path=关于
  • 首选项：根=通用及path= ACCESSIBILITY
  • 首选项：根= AIRPLANE_MODE
  • 首选项：根=通用及path= AUTOLOCK
  • 首选项：根=通用及path= USAGE / CELLULAR_USAGE
  • 首选项：根=亮度
  • 首选项：根=蓝牙
  • 首选项：根=通用及path= DATE_AND_TIME
  • 首选项：根= FACETIME
  • 首选项：根=通用
  • 首选项：根=通用及path=键盘
  • 首选项：根= CASTLE
  • 首选项：根=城堡＆path= STORAGE_AND_BACKUP
  • 首选项：根=通用及path= INTERNATIONAL
  • 首选项：根= LOCATION_SERVICES
  • 首选项：根= ACCOUNT_SETTINGS
  • 首选项：根= MUSIC
  • 首选项：根=音乐与path= EQ
  • 首选项：根=音乐与path= VolumeLimit
  • 首选项：根=通用及path=networking
  • 首选项：根= NIKE_PLUS_IPOD
  • 首选项：根= NOTES
  • 首选项：根= NOTIFICATIONS_ID
  • 首选项：根=电话
  • 首选项：根=照片
  • 首选项：根=通用及path= ManagedConfigurationList
  • 首选项：根=通用及path=复位
  • 首选项：根=声音和path=铃声
  • 首选项：根= Safari浏览器
  • 首选项：根=通用及path=助理
  • 首选项：根=声音
  • 首选项：根=通用及path= SOFTWARE_UPDATE_LINK
  • 首选项：根= STORE
  • 首选项：根= TWITTER
  • 首选项：根= FACEBOOK
  • prefs：root = General＆path = USAGE prefs：root = VIDEO
  • 首选项：根=通用及path=networking/ VPN
  • 首选项：根=壁纸
  • 首选项：根= WIFI
  • 首选项：根= INTERNET_TETHERING
  • 首选项：根=电话及path=阻止
  • 首选项：根= DO_NOT_DISTURB

注意：networking设置不会在模拟器中打开，但链接将在真实设备上运行。

在iOS 8 +中，您可以执行以下操作： 

  func buttonClicked(sender:UIButton) { UIApplication.sharedApplication().openURL(NSURL(string: UIApplicationOpenSettingsURLString)) }

使用@ vivek的提示我开发了一个基于Swift 3的utils类，希望您能够欣赏！ 

 import Foundation import UIKit public enum PreferenceType: String { case about = "General&path=About" case accessibility = "General&path=ACCESSIBILITY" case airplaneMode = "AIRPLANE_MODE" case autolock = "General&path=AUTOLOCK" case cellularUsage = "General&path=USAGE/CELLULAR_USAGE" case brightness = "Brightness" case bluetooth = "Bluetooth" case dateAndTime = "General&path=DATE_AND_TIME" case facetime = "FACETIME" case general = "General" case keyboard = "General&path=Keyboard" case castle = "CASTLE" case storageAndBackup = "CASTLE&path=STORAGE_AND_BACKUP" case international = "General&path=INTERNATIONAL" case locationServices = "LOCATION_SERVICES" case accountSettings = "ACCOUNT_SETTINGS" case music = "MUSIC" case equalizer = "MUSIC&path=EQ" case volumeLimit = "MUSIC&path=VolumeLimit" case network = "General&path=Network" case nikePlusIPod = "NIKE_PLUS_IPOD" case notes = "NOTES" case notificationsId = "NOTIFICATIONS_ID" case phone = "Phone" case photos = "Photos" case managedConfigurationList = "General&path=ManagedConfigurationList" case reset = "General&path=Reset" case ringtone = "Sounds&path=Ringtone" case safari = "Safari" case assistant = "General&path=Assistant" case sounds = "Sounds" case softwareUpdateLink = "General&path=SOFTWARE_UPDATE_LINK" case store = "STORE" case twitter = "TWITTER" case facebook = "FACEBOOK" case usage = "General&path=USAGE" case video = "VIDEO" case vpn = "General&path=Network/VPN" case wallpaper = "Wallpaper" case wifi = "WIFI" case tethering = "INTERNET_TETHERING" case blocked = "Phone&path=Blocked" case doNotDisturb = "DO_NOT_DISTURB" } 
 enum PreferenceExplorerError: Error { case notFound(String) } open class PreferencesExplorer { // MARK: - Class properties - static private let preferencePath = "App-Prefs:root" // MARK: - Class methods - static func open(_ preferenceType: PreferenceType) throws { let appPath = "\(PreferencesExplorer.preferencePath)=\(preferenceType.rawValue)" if let url = URL(string: appPath) { if #available(iOS 10.0, *) { UIApplication.shared.open(url, options: [:], completionHandler: nil) } else { UIApplication.shared.openURL(url) } } else { throw PreferenceExplorerError.notFound(appPath) } } }

这是非常有用的，因为这个API将会改变，你可以一次又一次地重构！

来自特定于应用程序的URL计划的第一个响应在iOS 10.3上适用于我。 

 if let appSettings = URL(string: UIApplicationOpenSettingsURLString + Bundle.main.bundleIdentifier!) { if UIApplication.shared.canOpenURL(appSettings) { UIApplication.shared.open(appSettings) } }

App-Prefs:root=Privacy&path=LOCATION为我find一般位置设置。 注意：只适用于设备。

在模拟器的ios10 / Xcode 8中： 

 UIApplication.shared.openURL(URL(string:UIApplicationOpenSettingsURLString)!)

作品 

 UIApplication.shared.openURL(URL(string:"prefs:root=General")!)

才不是。

我已经看到这行代码 

 UIApplication.sharedApplication() .openURL(NSURL(string:"prefs:root=General")!)

是不工作，它不适合我在ios10 / Xcode 8，只是一个小的代码差异，请replace这个 

 UIApplication.sharedApplication().openURL(NSURL(string:"App-Prefs:root=General")!)

Swift3 

 UIApplication.shared.openURL(URL(string:"prefs:root=General")!)

用。。。来代替 

 UIApplication.shared.openURL(URL(string:"App-Prefs:root=General")!)

希望它有帮助。 干杯。

添加到@ Luca Davanzo

iOS 11，一些权限设置已经移动到应用程序path：

iOS 11支持 

  static func open(_ preferenceType: PreferenceType) throws { var preferencePath: String if #available(iOS 11.0, *), preferenceType == .video || preferenceType == .locationServices || preferenceType == .photos { preferencePath = UIApplicationOpenSettingsURLString } else { preferencePath = "\(PreferencesExplorer.preferencePath)=\(preferenceType.rawValue)" } if let url = URL(string: preferencePath) { if #available(iOS 10.0, *) { UIApplication.shared.open(url, options: [:], completionHandler: nil) } else { UIApplication.shared.openURL(url) } } else { throw PreferenceExplorerError.notFound(preferencePath) } }

在iOS 10和Swift 3中，使用下面的代码： 

 UIApplication.shared.open(URL.init(string: "App-Prefs:root=General")!, options: [:]) { (success) in }

SWIFT 3

这可能需要您的应用程序的具体设置，如果这就是你要找的。 

 UIApplication.shared.openURL(URL(string: UIApplicationOpenSettingsURLString)!)

如上所述@niravdesai说，应用程序首选项。 我发现App-Prefs:适用于iOS 9,10和11testing的设备。 作为prefs:只适用于iOS 9。

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