是否可以在Angular ng-options中连接值

基本上，我试图填充select框，但连接来自first_name列和last_name列的值。

我想做什么（不起作用）：

 <select ng-model="buyers" ng-options="b.id as (b.first_name + " " + b.last_name) for b in buyers"></select> 

什么工作：

 <select ng-model="buyers" ng-options="b.id as b.first_name for b in buyers"></select> 

Answer 1

引号是重要的。 它不会使用双引号内的双引号或单引号内的单引号。

什么工作：

 <select ng-model="buyers" ng-options='b.id as (b.first_name + " " + b.last_name) for b in buyers'></select> 

Answer 2

你可以使用这个合成器连接一个string：

 ng-options="ix + ' ' + iy for i in items" 

以下代码片断连接了firstname和lastname ：

 angular.module('myApp', []); function MyCtrl($scope) { $scope.names = [{firstname: 'Jon', lastname: 'Snow'}, {firstname: 'Rob', lastname: 'Stark'}, {firstname: 'Ned', lastname: 'Stark'}]; } 

 <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script> <div ng-app="myApp" ng-controller="MyCtrl"> <select ng-model="selected" ng-options="n.firstname + ' ' + n.lastname for n in names"></select> selected: {{selected}} </div>